Anodic Anode
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Chemistry Electrolytic Cells Help!?
Consider four different samples: aqueous LiBr , molten LiBr , aqueous LiF , and molten LiF . Current run through each sample produces one of the following products at the anode: liquid bromine, fluorine gas, or oxygen gas. Match each sample to its anodic product.
Consider four different samples: aqueous LiBr , molten LiBr , aqueous LiF , and molten LiF . Current run through each sample produces one of the following products at the anode: liquid bromine, fluorine gas, or oxygen gas. Match each sample to its anodic product.
Basically list each's anode and cathode.
Thanks so much, anything helps!
Using molten LiBr and molten LiF as electrolytes, u get Br2 and F2 at the anode respectively. This is because the the solution contains only Br- and F- as anions respectively. Hence they get oxidised as Br- = Br + e- and F- = F +e- respectively (e- means an electron)
But in aqueous state the solution contains both OH-, Br- and OH-, F- respectively. Since OH- has a greater tendency to be oxidised (or a more -ve standard reduction potential) it will get oxidised in preference to the other anions as 4OH- = O2 + 2H2O + 4e- and hence O2 is liberated.
In molten state at cathode Li is liberated and in the aq. state H2 is liberated coz it has a more +ve standard reduction potential.
